i still need more help from u.
i m a doing thesis on tensegrity structure and i am not getting perfectly how to design a canopy or a
foot overbridge on internet i am just getting design methods of any simple structure but not getting a continous structure of tensegrity.

if u have any thesis work on tensegrity from which i can take help then plz surely tell me.
and 1 more help i need from you is can u tell me which is the best software for doing work on tensegrity at present i am using staad pro software for the work

and this site is amazing from this i can have many details thankx
http://complexity.xozzox.de/tensegrity.html

We can suggest you the following useful resources:
http://www.liftarchitects.com/journal/2007/10/5/tensegrity-wall.html
http://www.liftarchitects.com/journal/2007/2/22/adaptive-tensegrity.html
http://complexity.xozzox.de/tensegrity.html

good luck!

You should subdivide the surface using the Iso surfaces component, with a 2D interval/domain input. The boundaries of the 2D interval control the subdivision. You could use sliders to control the 2D Interval/Domain, which in turn drives the subdivision.

Hope that helps,
Best

I am a novice in GH and I am trying to do the definition for the canopy, but due to my inexperience I have problems producing it. I stopped at “Add controls for the number of subdivisions”; should I use Control Points Component? I don’t know what I am doing wrong, but what I have by now is far from your result and I know I am only three components away from getting it.

Your help would be much appreciated.
Thanks.

About your question:
The surface is subdivided by creating a regular grid of points on it. In result each sub-surface is kind of a panel.

In order to create the roof’s construction, we should create the diagonals of each panel and pipe them.
Because each panel is a surface, it’s easier to use the “Eval Surface” component, which returns a specific point on the surface based on it’s UV mapping.

U and V could vary from 0.0 to 1.0. For ex: the point at (U: 0.5 V:0.5 ) is located at the center of the surface.

Given that we need the four corners of each panel-surface, we are using four Points located at U,V (0,0), (0,1), (1,0,) and (1,1) accordingly.

Hopefully that makes sense.
If it’s still not clear, drop us a message

Cheers

Draw the diagonals of each subdivided surface, by using the four surface points located at UV(0,0), UV(0,1), UV(1,0), UV(1,1)

thanku